37x+(x^2)=-100

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Solution for 37x+(x^2)=-100 equation:



37x+(x^2)=-100
We move all terms to the left:
37x+(x^2)-(-100)=0
determiningTheFunctionDomain x^2+37x-(-100)=0
We add all the numbers together, and all the variables
x^2+37x+100=0
a = 1; b = 37; c = +100;
Δ = b2-4ac
Δ = 372-4·1·100
Δ = 969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{969}}{2*1}=\frac{-37-\sqrt{969}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{969}}{2*1}=\frac{-37+\sqrt{969}}{2} $

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